Linux Bridge to static address question.

Dec 9, 2021
8
0
1
50
Need some help. New to Proxmox, and have watched numerous videos about how to setup a network for a VM. I have read the documentation as well and still don't grasp what I have to do to set this up. Everything is setup static, no DHCP in environment.
My host is on Linux bridge with 172.18.32.44/24 GW is 172.18.32.1, this is connected to NIC "A" I can get to it just fine and other machines see this host.
Completely separate NIC, which we will call NIC "B" will have VM. So for the moment, I want 1 NIC to got to 1 VM.
eno1 will be the network device, I will bridge eno1 and create vmbr2. Then I need vm to have IP address of 172.18.37.10.
I can not ask for additional IP addresses.
I need eno1 to pass 172.18.37.10 to the vm with the same IP address. Is this possible?
 
you don't need to define ip address on bridge, to get this subnet/ip woking inside the vm.
bridge are simply layer2, they don't care about ip address.

ip on vmbrX are only use to have management ip on proxmox.
 
I have tried that and is it still does not work.
I have a nic card connected to a trunked switch, because I have to use vlan 37 for my VM.
eno1 with no IP address, goes to vmbr1 with no ip address. I modified the file to allow 1-4094 in vlan tagging, typically it's 2-4094.
On my VM i used the vmbr1 to connect my machine to the network. I set the IP and used the gateway i set for the proxmox management.
So my vm network is this:
1639406783494.png
 
I have tried that and is it still does not work.
I have a nic card connected to a trunked switch, because I have to use vlan 37 for my VM.
eno1 with no IP address, goes to vmbr1 with no ip address. I modified the file to allow 1-4094 in vlan tagging, typically it's 2-4094.
On my VM i used the vmbr1 to connect my machine to the network. I set the IP and used the gateway i set for the proxmox management.
So my vm network is this:
View attachment 32339
your gateway (x.x.32.x)is not in the same network (x.x.37.x) than your ipaddress, so it's impossible to each it.