Cronjob question

[bfish2]

I have a command in crontab -e to run nightly:

tar czvf /mnt/pve/NAS_Storage/host_bu/proxmox03-backup-$(date +%F).tar.gz /etc/pve

It is not producing the output.

When i look at the journal I see



which is essentially the command WITHOUT /etc/pve at the end, which is the source directory being copied.

What does that mean is wrong?

Thanks in advance!

 

[bbgeek17]

There are likely two issues:
a) % is a special character in crontab (man 5 crontab) https://linux.die.net/man/5/crontab#:~:text=are not allowed.-,The,-"sixth" field (the
b) you are having issues with PATH https://forum.proxmox.com/threads/b...p-based-on-status-crontab.143845/#post-646704

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Blockbridge : Ultra low latency all-NVME shared storage for Proxmox - https://www.blockbridge.com/proxmox

 

[bfish2]

There are likely two issues:
a) % is a special character in crontab (man 5 crontab) https://linux.die.net/man/5/crontab#:~:text=are not allowed.-,The,-"sixth" field (the
b) you are having issues with PATH https://forum.proxmox.com/threads/b...p-based-on-status-crontab.143845/#post-646704

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Blockbridge : Ultra low latency all-NVME shared storage for Proxmox - https://www.blockbridge.com/proxmox

Thank you! You led me in the right direction.

What is needed is a backslash in front of the % tomake the % be taken literally and NOT as a "new line":

0 0 * * * tar czvf /mnt/pve/NAS_Storage/host_bu/proxmox01-backup-$(date +\%F).tar.gz /etc/pve